To find the equation of the trend line in slope-intercept form (y = mx + b), we need to determine the slope (m) and y-intercept (b).
From the given points, we can see that the line passes through the points (0, 12), (4, 16), and (6, 18).
First, let's find the slope (m):
m = (change in y) / (change in x)
m = (18 - 12) / (6 - 0)
m = 6 / 6
m = 1
Next, let's find the y-intercept (b):
Using the point (0, 12) and the known slope (m = 1), we can use the slope-intercept form to solve for b:
12 = 0(1) + b
12 = b
Therefore, the equation of the trend line in slope-intercept form is:
y = 1x + 12
y = x + 12
Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y=__
1 answer
1 answer