Looking at the periodic table, determine the number of valence electrons present in a following neutral atoms.

Column A
1. Oxygen (O)
2. Aluminum (AI)
3. Neon (Ne)
4. Silicon (Si)
5. Magnesium (Mg)
6. Iodine (I)
7. Lithium (Li)
8. Nitrogen (N)

Column B
A. 7 valence electrons
B. 3 valence electrons
C. 4 valence electrons
D. 6 valence electrons
E. 5 valence electrons
F. 8 valence electrons
G. 2 valence electrons
H. 1 valence electrons

1 answer

1. Oxygen (O) - 6 valence electrons
2. Aluminum (Al) - 3 valence electrons
3. Neon (Ne) - 8 valence electrons
4. Silicon (Si) - 4 valence electrons
5. Magnesium (Mg) - 2 valence electrons
6. Iodine (I) - 7 valence electrons
7. Lithium (Li) - 1 valence electron
8. Nitrogen (N) - 5 valence electrons

So the answers would be:
1. E (5 valence electrons)
2. B (3 valence electrons)
3. F (8 valence electrons)
4. C (4 valence electrons)
5. G (2 valence electrons)
6. A (7 valence electrons)
7. H (1 valence electron)
8. E (5 valence electrons)