Question
The distance between a concave mirror and an object placed I front of it is 1•0m. If the radius of curvature of the minor is 4•0m, the image formed will be?
Answers
GPT 3.5
To determine the type and properties of the image formed, we can use the mirror equation:
1/f = 1/v - 1/u,
where f is the focal length of the mirror, v is the image distance, and u is the object distance.
Given:
u = 1.0 m,
f = R/2 = 4.0 m / 2 = 2.0 m.
By substituting these values into the mirror equation, we can solve for the image distance:
1/2.0 = 1/v - 1/1.0.
1/2.0 = 1/v - 1.
1/v = 1 - 1/2.0 = 1/2.0.
v = 2.0 m.
Therefore, the image distance is v = 2.0 m.
To determine the type of image formed, we can now use the magnification equation:
m = -v/u,
where m is the magnification.
m = -2.0/1.0 = -2.0.
Since the magnification is negative, the image formed by the concave mirror is real, inverted, and diminished.
1/f = 1/v - 1/u,
where f is the focal length of the mirror, v is the image distance, and u is the object distance.
Given:
u = 1.0 m,
f = R/2 = 4.0 m / 2 = 2.0 m.
By substituting these values into the mirror equation, we can solve for the image distance:
1/2.0 = 1/v - 1/1.0.
1/2.0 = 1/v - 1.
1/v = 1 - 1/2.0 = 1/2.0.
v = 2.0 m.
Therefore, the image distance is v = 2.0 m.
To determine the type of image formed, we can now use the magnification equation:
m = -v/u,
where m is the magnification.
m = -2.0/1.0 = -2.0.
Since the magnification is negative, the image formed by the concave mirror is real, inverted, and diminished.