The system of equations is:
8x - 6y = 48
8x + 6y = 48
To find the number of solutions, we can eliminate one of the variables by adding the two equations together:
(8x - 6y) + (8x + 6y) = 48 + 48
16x = 96
x = 96/16
x = 6
Substituting x = 6 into either of the original equations, we can find the value for y:
8(6) - 6y = 48
48 - 6y = 48
-6y = 0
y = 0
Therefore, the system of equations has only one solution: (x, y) = (6, 0).
How many solutions does the system of equations have? 8x−6y=48 8x+6y=48 (1 point)
1 answer