4x + 3y = 15 and y = x + 5 linear equation

Answer 1

To solve the system of equations, we can substitute the value of y from the second equation into the first equation:

4x + 3(x + 5) = 15
4x + 3x + 15 = 15
7x + 15 = 15
7x = 0
x = 0

Now substitute the value of x back into the second equation to find the value of y:

y = 0 + 5
y = 5

So, the solution to the system of equations is x = 0 and y = 5.