To find the percent composition by volume of aluminum, we need to find the total volume of the magnesium alloy first. We have:
$341.2 + 30.96 + 488.0 + 672.0=1532.16$ cubic centimeters.
The percent composition by volume of aluminum is then:
$\frac{30.96\text { cubic decimeters (dm}^3\text {)}\times100}{1532.16\text { cubic centimeters (cm}^3\text {)}}=\boxed{2.02\%}$.
A magnesium alloy contains the following volumes of each element: 341.2 cubic decimeters of magnesium, 30.96 cubic decimeters of aluminum, 488.0 cubic centimeters of manganese, and 672.0 cubic centimeters of zinc. Find the percent composition by volume of aluminum. Round the answer to the nearest hundredth percent.
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