To solve this problem, we can use the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
The momentum (p) of an object is given by the equation:
p = mass x velocity
Before the collision, the total momentum is the sum of the momentum of the cue stick and the ball:
Total momentum before collision = (mass of cue stick x velocity of cue stick) + (mass of ball x velocity of ball)
Total momentum before collision = (0.5 kg x 2.5 m/s) + (0.2 kg x 0 m/s) (since the ball is initially at rest)
Total momentum before collision = 1.25 kg.m/s
After the collision, the total momentum is the sum of the momentum of the cue stick and the ball:
Total momentum after collision = (mass of cue stick x velocity of cue stick) + (mass of ball x velocity of ball)
We are given that the cue stick hits the ball with a velocity of 2.5 m/s.
Total momentum after collision = (0.5 kg x 0 m/s) + (0.2 kg x velocity of ball)
Since the initial momentum of the ball is zero (since it is at rest), we can simplify the equation:
Total momentum after collision = (0.2 kg x velocity of ball)
We know that the total momentum before the collision is equal to the total momentum after the collision:
1.25 kg.m/s = (0.2 kg x velocity of ball)
To find the velocity of the ball after the collision, we can rearrange the equation:
velocity of ball = 1.25 kg.m/s / 0.2 kg
velocity of ball = 6.25 m/s
So, the velocity of the ball after it is hit is approximately 6.3 m/s.
The correct answer is: 6.3 m/s
A cue stick has a mass of 0.5 kg. The cue stick hits a ball with a mass of 0.2 kg at a velocity of 2.5 m/s. What is the velocity of the ball after it is hit? (1 point)
Responses
8.3 m/s
8.3 m/s
3.6 m/s
3.6 m/s
6.3 m/s
6.3 m/s
2.5 m/s
1 answer
0 answers