Question

√
What is the irrational cube root 40 rewritten as a product of an integer and another irrational cube root?
O 8√5
O 2√5
O-2√5
O 2√10

Answer 1

To rewrite the irrational cube root of 40 as a product of an integer and another irrational cube root, we need to find a perfect cube factor of 40.

The perfect cube factors of 40 are 1, 8, and 27.

Since 40 is not a perfect cube, the only factor we can use to rewrite it as a product of an integer and another irrational cube root is 8.

Therefore, the correct answer is O 8√5.