To solve the system of equations, we can use the method of elimination or substitution.
Using the elimination method, we can multiply both sides of the first equation by 5 and the second equation by 3 to eliminate the coefficients of x.
15x - 20y = 200
15x - 15y = 165
Subtracting the second equation from the first eliminates the x term:
-5y = 35
Dividing both sides by -5:
y = -7
Now we can substitute this value of y into one of the original equations to solve for x. Substituting y = -7 into the first equation:
3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4
Therefore, the solution to the system of equations is (4, -7).
Solve the system of equations.
3x−4y=40
5x−5y=55 (1 point)
Responses
(18, 7)
left parenthesis 18 comma 7 right parenthesis
(8,−3)
left parenthesis 8 comma negative 3 right parenthesis
(4,−7)
left parenthesis 4 comma negative 7 right parenthesis
(14, 3)
1 answer