Question
draw the bond polarity of bf3
Answers
GPT 3.5
To determine the bond polarity of BF3 (boron trifluoride), we need to find the difference in electronegativity between boron (B) and fluorine (F).
Step 1: Find the electronegativity values of each element.
The electronegativity of boron (B) is 2.04, and the electronegativity of fluorine (F) is 3.98.
Step 2: Find the difference in electronegativity.
∆EN = Electronegativity of F - Electronegativity of B
= 3.98 - 2.04
= 1.94
Step 3: Determine bond polarity based on the electronegativity difference.
If ∆EN is between 0.5 and 1.7, the bond is considered polar covalent.
If ∆EN is greater than 1.7, the bond is considered ionic.
In this case, since the electronegativity difference (∆EN = 1.94) is between 0.5 and 1.7, the bond between B and F in BF3 is considered polar covalent.
A polar covalent bond is represented using a delta (δ) symbol to indicate a partial positive charge (δ+) on the less electronegative atom (Boron, B) and a partial negative charge (δ-) on the more electronegative atom (Fluorine, F).
Here is a simple representation of the bond polarity in BF3:
F(δ-) - B(δ+) - F(δ-) - F(δ-)
Step 1: Find the electronegativity values of each element.
The electronegativity of boron (B) is 2.04, and the electronegativity of fluorine (F) is 3.98.
Step 2: Find the difference in electronegativity.
∆EN = Electronegativity of F - Electronegativity of B
= 3.98 - 2.04
= 1.94
Step 3: Determine bond polarity based on the electronegativity difference.
If ∆EN is between 0.5 and 1.7, the bond is considered polar covalent.
If ∆EN is greater than 1.7, the bond is considered ionic.
In this case, since the electronegativity difference (∆EN = 1.94) is between 0.5 and 1.7, the bond between B and F in BF3 is considered polar covalent.
A polar covalent bond is represented using a delta (δ) symbol to indicate a partial positive charge (δ+) on the less electronegative atom (Boron, B) and a partial negative charge (δ-) on the more electronegative atom (Fluorine, F).
Here is a simple representation of the bond polarity in BF3:
F(δ-) - B(δ+) - F(δ-) - F(δ-)