Question
a bag contains 8 identical balls of which 5 are yellow and 3 are white.1 ball is removed,its colour is noted and is replaced in the bag.a second ball is drawn.by drawing a table,find the probability(a)both balls are yellow(b)both are white (c)only 1 is white.
Both yellow=(5/8)*(5/8)
Both white =(3/8)*(3/8)
one of each=2*(5/8)*(3/8)
should sum to 1.00
Both yellow=(5/8)*(5/8)
Both white =(3/8)*(3/8)
one of each=2*(5/8)*(3/8)
should sum to 1.00