Solve the system of equations.

Question

2x+8y=8
2x−4y=−16

Answer 1

To solve the system of equations:

1) 2x + 8y = 8
2) 2x - 4y = -16

We can solve by elimination or substitution.

Using elimination, we can multiply equation 2) by 2 to make the x-coefficients equal:
4x - 8y = -32

Then, we can add equation 1) and equation 2) together:
(2x + 8y) + (4x - 8y) = 8 + (-32)
6x = -24
Divide both sides by 6 to solve for x:
x = -24/6
x = -4

Then, we can substitute this value of x back into either equation 1) or equation 2) to solve for y. Let's use equation 1):

2(-4) + 8y = 8
-8 + 8y = 8
Add 8 to both sides:
8y = 16
Divide both sides by 8 to solve for y:
y = 2

Therefore, the solution to the system of equations is x = -4 and y = 2.