Question

Solve the system of two linear equations. −3x−4y=−23 3x−5y=5 (1 point) Responses (5, 2) left parenthesis 5 comma 2 right parenthesis (5,−2) left parenthesis 5 comma negative 2 right parenthesis (−5, 2) left parenthesis negative 5 comma 2 right parenthesis (−5,−2)

Answer 1

To solve the system of equations:
−3x − 4y = −23
3x − 5y = 5

You can use the elimination method.

Multiply the first equation by 3 and the second equation by -3 to eliminate x:

-9x - 12y = -69
-9x + 15y = -15

Adding these equations eliminates x:

-12y + 15y = -69 - 15
3y = -84
y = -28

Substitute the value of y into either original equation to find x, using the first equation:

-3x - 4(-28) = -23
-3x + 112 = -23
-3x = -135
x = 45

Therefore, the solution to the system of equations is (45, -28).