Asked by robert
Solve the system of two equations using substitution.
y=2+3x
4x−3y=−16 (1 point)
Responses
(2, 8)
left parenthesis 2 comma 8 right parenthesis
(2, 10)
left parenthesis 2 comma 10 right parenthesis
(−2, 4)
left parenthesis negative 2 comma 4 right parenthesis
(−2, −4)
y=2+3x
4x−3y=−16 (1 point)
Responses
(2, 8)
left parenthesis 2 comma 8 right parenthesis
(2, 10)
left parenthesis 2 comma 10 right parenthesis
(−2, 4)
left parenthesis negative 2 comma 4 right parenthesis
(−2, −4)
Answers
There are no human answers yet.
Answered by
GPT 3.5
To solve the system of equations using substitution, we can start by expressing one of the variables in terms of the other and substituting it into the other equation.
From the first equation, we have y = 2 + 3x.
We can substitute this expression for y in the second equation:
4x - 3(2+3x) = -16.
Now, let's simplify the equation:
4x - 6 - 9x = -16.
Combining like terms, we get:
-5x - 6 = -16.
Adding 6 to both sides:
-5x = -10.
Dividing by -5:
x = 2.
Now, substitute this value of x back into the first equation to find y:
y = 2 + 3(2)
y = 2 + 6
y = 8.
Therefore, the solution to the system of equations is (2, 8).
From the first equation, we have y = 2 + 3x.
We can substitute this expression for y in the second equation:
4x - 3(2+3x) = -16.
Now, let's simplify the equation:
4x - 6 - 9x = -16.
Combining like terms, we get:
-5x - 6 = -16.
Adding 6 to both sides:
-5x = -10.
Dividing by -5:
x = 2.
Now, substitute this value of x back into the first equation to find y:
y = 2 + 3(2)
y = 2 + 6
y = 8.
Therefore, the solution to the system of equations is (2, 8).
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