To solve the system of equations using elimination with multiplication, we want to eliminate one variable by multiplying both equations by appropriate numbers.
First, let's multiply the second equation by 2 to eliminate the coefficient of "-2x":
2(-2x + 4y) = 2(30)
-4x + 8y = 60
Now, we have the following system of equations:
4x - 6y = -48
-4x + 8y = 60
By adding the two equations together, we can eliminate the "x" variable:
(4x - 6y) + (-4x + 8y) = -48 + 60
-6y + 8y = 12
2y = 12
y = 6
Substitute the value of "y" back into one of the original equations:
4x - 6(6) = -48
4x - 36 = -48
4x = -48 + 36
4x = -12
x = -12/4
x = -3
Therefore, the solution to the system of equations is (x, y) = (-3, 6).
Solve the system of two equations using elimination with multiplication.
4x−6y=−48
−2x+4y=30 (1 point)
Responses
(−3, 6)
left parenthesis negative 3 comma 6 right parenthesis
(−33,−9)
left parenthesis negative 33 comma negative 9 right parenthesis
(3, 9)
left parenthesis 3 comma 9 right parenthesis
(−21,−6)
1 answer