To determine whether the values 3 and 4 are solutions to the given quadratic equation, we substitute these values into the equation and check whether the equation is satisfied.
For x = 3:
(3)^2 - 7(3) + 12 = 9 - 21 + 12 = 0
Since the equation is satisfied, x = 3 is a solution.
For x = 4:
(4)^2 - 7(4) + 12 = 16 - 28 + 12 = 0
Since the equation is satisfied, x = 4 is also a solution.
Therefore, both x = 3 and x = 4 are solutions to the quadratic equation.
The correct answer is Option #3: Both x = 3 and x = 4 are solutions.
etermine whether the values 3 and 4 are solutions to the quadratic equation x2−7x+12=0 , and then select the correct answer from the following options. Option #1: Only x=3 is a solution. Option #2: Only x=4 is a solution. Option #3: Both x=3 and x=4 are solutions. Option #4: Neither x=3 nor x=4 is a solution. (1 point) Option # Remaining Attempts : 3 Skip to navigation
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