If EF ≅ FG, EH = 2s, and GH = s + 28, what is the value of s?

Answer 1

If EF ≅ FG, then EF = FG. And if EH = 2s and GH = s + 28, we know that FH = EH + GH = 2s + (s + 28) = 3s + 28.

Since EF = FG, we can conclude that EFH and FGH form a straight line. So EFH + FGH = 180°.

From EFH, we have:

180° = 90° + (3s + 28)
90° = 3s + 28
62° = 3s
s = 62°/3
s ≈ <<20.666666666666668=20.67>>20.67. Answer: \boxed{20.67}.