We can solve this system of equations by multiplying all three equations together:
(xy)(yz)(zx) = 15 * 35 * 21
xyz * xyz * xyz = 15 * 35 * 21
(xyz)^2 = 15 * 35 * 21
xyz = √(15 * 35 * 21)
We know that xyz is positive because all three variables (x, y, and z) are positive.
Now, if we divide each equation by the corresponding variable, we get:
xy / x = y
yz / y = z
zx / z = x
Substituting the given values, we have:
y = 15 / x
z = 35 / y
x = 21 / z
Substituting these values into the equation xyz = √(15 * 35 * 21), we get:
(21 / z) * (15 / (15 / x)) * (35 / (35 / y)) = √(15 * 35 * 21)
21 * x * 35 * y * 15 * z = √(15 * 35 * 21)^2
(21 * 35 * 15) * xyz = 15 * 35 * 21
xyz = 1
Therefore, the positive valued solution to this system of equations is xyz = 1.
The sum of the positive valued solution is 1 + 1 + 1 = 3.
Determine the sum of the positive valued solution to the simultaneous equations:
xy = 15, yz = 35,zx = 21
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