A firm is assigned the network part 128.171. It selects a 8-bit subnet part. a) Draw the bits for the four octets of the IP address of the first host on the first subnet. (Hint: Use Windows Calculator.)

Question

b) Convert this answer into dotted decimal notation.
c) Draw the bits for the second host on the third subnet. (In binary, 2 is 10, while 3 is 11.)
d) Convert this into dotted decimal notation.
e) Draw the bits for the last host on the third subnet.
f) Convert this answer into dotted decimal notation.

Answer 1

Remember for any type of address the first address 00000000(0) and last address 11111111(255) are not used, therefore first host address begins with 1 and last usuable host is 254 same goes for the subnet address.

Solution:

a)10000000.10101011.00000001.00000001

b)128.171.1.1

c)10000000.10101011.00000011.00000010

d)128.171.3.2

e)10000000.10101011.00000011.11111110

f)128.171.3.254