Question

the number of moles of O2 in 38.4 L of O2 gas Express your answer with the appropriate units

Answer 1

To calculate the number of moles of O2 gas, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L*atm/mol*K)
T = temperature (in Kelvin)

Assuming the temperature and pressure are constant, we can rearrange the equation to solve for n:

n = PV /RT

Given:
V = 38.4 L

We need to know the pressure and temperature to calculate the number of moles accurately. However, if we assume standard conditions (1 atm pressure and 273.15 K temperature), we can use those values:

P = 1 atm
R = 0.0821 L*atm/mol*K
T = 273.15 K

Substituting these values into the equation:

n = (1 atm * 38.4 L) / (0.0821 L*atm/mol*K * 273.15 K)
n = 1.428 moles

Therefore, the number of moles of O2 gas in 38.4 L is 1.428 moles.