Question

9.(-33)0+3/2(8-27^0).

Answer 1

To solve this expression, we will follow the order of operations (PEMDAS/BODMAS):

1. Start with the operations inside the parentheses: (-27^0)
- Anything raised to the power of 0 is always 1.
- So, (-27^0) becomes (-27^1) which is equal to -27.

The expression becomes: (-33)0 + 3/2(8 - (-27))

2. Next, perform the subtraction inside the parentheses: (8 - (-27))
- Subtracting a negative number is the same as adding the positive number.
- So, (8 - (-27)) becomes (8 + 27) which is equal to 35.

The expression becomes: (-33)0 + 3/2(35)

3. Now, multiply 3/2 by 35:
- Multiply the numerator and denominator separately: 3 x 35 = 105 and 2 x 1 = 2.
- So, 3/2(35) becomes 105/2 or 52.5.

The expression becomes: (-33)0 + 52.5

4. Next, perform the multiplication: (-33)0
- Anything raised to the power of 0 is always 1.
- So, (-33)0 becomes 1.

The expression becomes: 1 + 52.5

5. Finally, perform the addition: 1 + 52.5
- 1 + 52.5 equals 53.5.

The final answer is 53.5.