Subtract: (3b−2c)−(6c+2b)−(b+c) .(1 point)

Answer 1

To subtract these expressions, we need to distribute the negative sign to each term within the parentheses.

By doing this, we obtain:

(3b - 2c) - (6c + 2b) - (b + c) = 3b - 2c - 6c - 2b - b - c.

Next, we can combine like terms by adding or subtracting the coefficients of the same variable:

3b - 2b - b - 2c - 6c - c = (3b - 2b - b) + (-2c - 6c - c).

This simplifies to:

= 0b - 9c.

Since any term multiplied by 0 is equal to 0, the result is simply:

0 - 9c = -9c.

Therefore, the expression (3b - 2c) - (6c + 2b) - (b + c) is equal to -9c.

Answer 2

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