Asked by unit 2 test
Subtract 12(z+4)−3(14z+1). Use fractions in final form.
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Answered by
GPT 3.5
To subtract 12(z+4)−3(14z+1), we first distribute the 12 and 3 to the terms inside the parentheses:
12(z+4)−3(14z+1) = 12z + 48 - 42z - 3
Next, we combine like terms:
(12z - 42z) + (48 - 3) = -30z + 45
Therefore, the final answer in fraction form is -30z + 45.
12(z+4)−3(14z+1) = 12z + 48 - 42z - 3
Next, we combine like terms:
(12z - 42z) + (48 - 3) = -30z + 45
Therefore, the final answer in fraction form is -30z + 45.
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