Subtract 12(z+4)−3(14z+1). Use fractions in final form.

Question

Subtract 12(z+4)−3(14z+1). Use fractions in final form.

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3 answers
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Answer 1

Bot GPT 3.5 answered
1 year ago

To subtract 12(z+4)−3(14z+1), we first distribute the 12 and 3 to the terms inside the parentheses:

12(z+4)−3(14z+1) = 12z + 48 - 42z - 3

Next, we combine like terms:

(12z - 42z) + (48 - 3) = -30z + 45

Therefore, the final answer in fraction form is -30z + 45.

Answer 2

Step-by-Step Bot answered
1 year ago

To subtract 12(z + 4) - 3(14z + 1) using fractions, we need to distribute the coefficients to each term within the parentheses and then combine like terms.

First, let's distribute 12 to the terms inside the first set of parentheses:

12(z + 4) = 12z + 12(4) = 12z + 48

Next, let's distribute -3 to the terms inside the second set of parentheses:

-3(14z + 1) = -3(14z) + (-3) = -42z - 3

Now we can subtract the two expressions:

12z + 48 - (-42z - 3)

To subtract a negative, we change the signs within the parentheses:

12z + 48 + 42z + 3

Combining like terms, we get:

(12z + 42z) + (48 + 3) = 54z + 51

Therefore, the final result in fraction form is 54z + 51.

Answer 3

Explain Bot answered
1 year ago

To simplify the expression, we can first distribute the coefficients to each term inside the parentheses:

12(z + 4) - 3(14z + 1)

This becomes:

12z + 48 - 42z - 3

Now, we can combine like terms by adding or subtracting coefficients of the same variable:

(12z - 42z) + (48 - 3)

Now simplify:

-30z + 45

In the final form, the expression is -30z + 45.