To find the solution to both equations, we need to find the intersection point of the two lines. By substituting the value of y in the second equation into the first equation, we can solve for x.
Substituting y = x + 5 into 4x + 3y = 15:
4x + 3(x + 5) = 15
4x + 3x + 15 = 15
7x + 15 = 15
7x = 15 - 15
7x = 0
x = 0/7
x = 0
Now that we have the value of x, we can substitute it back into either equation to find the value of y. Let's use the second equation.
Substituting x = 0 into y = x + 5:
y = 0 + 5
y = 5
Therefore, the solution to both equations is (0, 5).
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4x + 3y = 15 y 15- 14- The intersection point is 13- 12- 11 10- -9- ∞06.200 -8- 7 6- -52 -4 3- 2- 1- -0- -10-9-8-7 -6 -5 -4 -3 -2 -1,0 1 23 F-11 -2- -3- -4- -5- ge 5 y = x + 5 6 7 8 9 10 Review the graphs of a system of two linear equations in two variables: 4x + 3y = 15 and y = x + 5. Find the solution to both equations. (1 point)
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