f*2PI = 1/sqrtLC
square both sides
(f*2PI)^2=1/LC
multiply both sides by C, divide both sides by (f*2PI)^2
I know that to solve:
f=1 over 2 pi sqrt LC for C, I have to use
C= 1 over L(2 pi f)^2
Can someone take me through the rearranging please. Thanks.
4 answers
f = 1/[2*pi*sqrt(LC)],
square both sides.
f^2 = 1/[4*pi^2*LC].
Cross multiply.
4*pi*2*LC*f^2 = 1
solve for C.
C = 1/[4*pi^2*f^2*L]
C = 1/[(2*pi*f)^2*L]=
1/L*(2*pi*f)^2
square both sides.
f^2 = 1/[4*pi^2*LC].
Cross multiply.
4*pi*2*LC*f^2 = 1
solve for C.
C = 1/[4*pi^2*f^2*L]
C = 1/[(2*pi*f)^2*L]=
1/L*(2*pi*f)^2
Thank you very much.
C=1/4perr square fsquare l
0 answers