Question

Can someone get me in the right direction to figure this problem?
The sides of a square are lengthened by 7 cm. The area becomes 256 cm^2 Find the length of one of the sides of the original square.
Much appreciated

Answer 1

Area of square = height * length. Since they are equal in a square, Area = Side Squared (A = s^2)

To get the new area, you need (s + 7)^2 = 256. Solve for s. Hint: What is the square root of 256?

I hope this helps. Thanks for asking.

Answer 2

The vertex and line of symmetry is constantly confusing me and I know how to do it can you help me get started to find all of the different needs of this question
f(x)=2x^2 +2x +8I need the x coordinates of the vertex, the y coordinates of the vertex the equation of the line of symmetry and the max/min of f(1/2) =17/2 is a min or max
I have been working on this and may have confused myself. I appreciate any help.