What value would cause the rational expression 5x+15/-2x^2-16x-32 to be undefined?

Answer 1

The rational expression 5x+15/-2x^2-16x-32 would be undefined when the denominator, -2x^2-16x-32, is equal to zero.

To find the value(s) that make the denominator zero, we can solve the quadratic equation -2x^2-16x-32 = 0.

First, let's divide the equation by -2 to simplify it: x^2 + 8x + 16 = 0.

Now, we can factor this quadratic equation: (x + 4)(x + 4) = 0.

This equation has a double root of -4, meaning that the expression would be undefined when x = -4.