To find the sum of the populations of the two cities, we can simply add the two numbers together.
3.45×10⁶ + 1.3×10⁵
To add these numbers in scientific notation, we need to line up the decimal places by moving the smaller number until it lines up with the larger number. In this case, we need to move the 1.3×10⁵ six places to the left to line up with the 3.45×10⁶.
1.3×10⁵ = 0.00013 × 10⁶ = 0.13×10⁶
Now we can add the two numbers:
3.45×10⁶ + 0.13×10⁶ = 3.58×10⁶
So, the sum of the populations of the two cities is 3.58×10⁶.
The correct answer is A. 3.58×10⁶.
The population of a city is given as 3.45×10⁶. A nearby city has a population of 1.3×10⁵. What is the sum of the populations of the two cities in scientific notation?
A. 3.58×10⁶
B. 4.75×10¹¹
C. 35.8+10⁵
D. 4.75×10⁵
7 answers
An empty dump truck weighs about 2.8×10⁵ pounds. How many does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation.
A. 4.33×10⁵ pounds
B. 15,302.8 pounds
C. 2.953×10⁵ pounds
D. 29,530 pounds
A. 4.33×10⁵ pounds
B. 15,302.8 pounds
C. 2.953×10⁵ pounds
D. 29,530 pounds
To find the weight of the dump truck with the added trash, we need to add the weight of the truck to the weight of the trash.
2.8×10⁵ pounds + 15,300 pounds
Since the added weight of the trash is not in scientific notation, we can rewrite it as:
15,300 = 1.53×10⁴
Now we can add the two numbers:
2.8×10⁵ pounds + 1.53×10⁴ pounds = 2.8×10⁵ pounds + 1.53×10⁴ pounds = 2.953×10⁵ pounds
So, the weight of the dump truck with the added trash is 2.953×10⁵ pounds.
The correct answer is C. 2.953×10⁵ pounds.
2.8×10⁵ pounds + 15,300 pounds
Since the added weight of the trash is not in scientific notation, we can rewrite it as:
15,300 = 1.53×10⁴
Now we can add the two numbers:
2.8×10⁵ pounds + 1.53×10⁴ pounds = 2.8×10⁵ pounds + 1.53×10⁴ pounds = 2.953×10⁵ pounds
So, the weight of the dump truck with the added trash is 2.953×10⁵ pounds.
The correct answer is C. 2.953×10⁵ pounds.
The half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463×10¹¹ years longer. What is the half-life of uranium-238? The answer should be in decimal form.
A. 516,300,000,000
B. 11,463,000,000
C. 4.4637 × 10¹¹
D. 447,000,000,000
A. 516,300,000,000
B. 11,463,000,000
C. 4.4637 × 10¹¹
D. 447,000,000,000
To find the half-life of uranium-238, we need to find the difference between the half-life of uranium-238 and uranium-235.
The half-life of uranium-238 is the half-life of uranium-235 plus the additional time of 4.463×10¹¹ years.
Half-life of uranium-238 = Half-life of uranium-235 + 4.463×10¹¹ years
The half-life of uranium-235 is given as 700,000,000 years.
Half-life of uranium-238 = 700,000,000 years + 4.463×10¹¹ years
To simplify this, we need to express 700,000,000 years in scientific notation:
700,000,000 = 7×10⁸ years
Now we can add the two numbers:
Half-life of uranium-238 = 7×10⁸ years + 4.463×10¹¹ years
To add the numbers in scientific notation, we need to align the decimals:
7×10⁸ years = 0.7×10¹⁰ years
Half-life of uranium-238 = 0.7×10¹⁰ years + 4.463×10¹¹ years = 5.163×10¹¹ years
So, the half-life of uranium-238 is 5.163×10¹¹ years.
The correct answer is A. 516,300,000,000.
The half-life of uranium-238 is the half-life of uranium-235 plus the additional time of 4.463×10¹¹ years.
Half-life of uranium-238 = Half-life of uranium-235 + 4.463×10¹¹ years
The half-life of uranium-235 is given as 700,000,000 years.
Half-life of uranium-238 = 700,000,000 years + 4.463×10¹¹ years
To simplify this, we need to express 700,000,000 years in scientific notation:
700,000,000 = 7×10⁸ years
Now we can add the two numbers:
Half-life of uranium-238 = 7×10⁸ years + 4.463×10¹¹ years
To add the numbers in scientific notation, we need to align the decimals:
7×10⁸ years = 0.7×10¹⁰ years
Half-life of uranium-238 = 0.7×10¹⁰ years + 4.463×10¹¹ years = 5.163×10¹¹ years
So, the half-life of uranium-238 is 5.163×10¹¹ years.
The correct answer is A. 516,300,000,000.
A mobile phone holds 1.28 × 10¹¹ bytes of storage. You can also pay more money to get an additional 384,000,000,000 bytes. How much storage would your phone have if you buy the additional bytes? The answer should be in scientific notation.
A. 385.28 × 10¹¹
B. 385,280,000,000
C. 5.12 × 10¹¹
D. 512 × 10⁹
A. 385.28 × 10¹¹
B. 385,280,000,000
C. 5.12 × 10¹¹
D. 512 × 10⁹
To find the total storage of the mobile phone after buying the additional bytes, we need to add the original storage to the additional storage.
1.28 × 10¹¹ bytes + 384,000,000,000 bytes
Since the additional storage is not in scientific notation, we can rewrite it as:
384,000,000,000 = 3.84 × 10¹¹
Now we can add the two numbers:
1.28 × 10¹¹ bytes + 3.84 × 10¹¹ bytes = 1.28 × 10¹¹ bytes + 3.84 × 10¹¹ bytes = 5.12 × 10¹¹ bytes
So, the mobile phone would have a total storage of 5.12 × 10¹¹ bytes.
The correct answer is C. 5.12 × 10¹¹.
1.28 × 10¹¹ bytes + 384,000,000,000 bytes
Since the additional storage is not in scientific notation, we can rewrite it as:
384,000,000,000 = 3.84 × 10¹¹
Now we can add the two numbers:
1.28 × 10¹¹ bytes + 3.84 × 10¹¹ bytes = 1.28 × 10¹¹ bytes + 3.84 × 10¹¹ bytes = 5.12 × 10¹¹ bytes
So, the mobile phone would have a total storage of 5.12 × 10¹¹ bytes.
The correct answer is C. 5.12 × 10¹¹.