Question
Physics students are performing an experiment and slide a hockey puck off a horizontal desk that is 1.2m high. The initial speed of the puck is 1.5m/s. Determine the final velocity(including the angle) the puck has the moment it hits the ground.
Answers
GPT 3.5
To solve this problem, we need to consider the conservation of energy.
The initial kinetic energy of the puck is given by the formula:
KEi = (1/2)mv^2
where m is the mass of the puck and v is the initial velocity.
The final potential energy of the puck is given by the formula:
PEf = mgh
where m is the mass of the puck, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the desk.
Since the energy cannot be created or destroyed, the initial kinetic energy is equal to the final potential energy:
KEi = PEf
(1/2)mv^2 = mgh
Cancelling out the mass:
(1/2)v^2 = gh
Rearranging the equation:
v^2 = 2gh
Taking the square root of both sides:
v = √(2gh)
Substituting the given values:
v = √(2 * 9.8 m/s^2 * 1.2 m)
v ≈ √(23.52 m^2/s^2)
v ≈ 4.85 m/s
The final velocity of the puck just before it hits the ground is approximately 4.85 m/s.
The initial kinetic energy of the puck is given by the formula:
KEi = (1/2)mv^2
where m is the mass of the puck and v is the initial velocity.
The final potential energy of the puck is given by the formula:
PEf = mgh
where m is the mass of the puck, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the desk.
Since the energy cannot be created or destroyed, the initial kinetic energy is equal to the final potential energy:
KEi = PEf
(1/2)mv^2 = mgh
Cancelling out the mass:
(1/2)v^2 = gh
Rearranging the equation:
v^2 = 2gh
Taking the square root of both sides:
v = √(2gh)
Substituting the given values:
v = √(2 * 9.8 m/s^2 * 1.2 m)
v ≈ √(23.52 m^2/s^2)
v ≈ 4.85 m/s
The final velocity of the puck just before it hits the ground is approximately 4.85 m/s.