Solve the system of equations.x=6y−3 2x+7y=13 (1 point)

Answer 1

The solution to the system of equations x=6y−3 and 2x+7y=13 are x = 3 and y = 1.

Answer 2

Solve the system of equations.8x−3y= −22 y=10+4x (1 point)

Answer 3

The solution to the system of equations 8x−3y= −22 and y=10+4x is x = -2 and y = -6.

Answer 4

its not -6

Answer 5

Apologies for the confusion. Let's solve it step by step:
First, plug y=10+4x from the second equation into the first:

8x - 3*(10 + 4x) = -22
8x - 30 - 12x = -22
-4x = 8
x = -2

Then, substitute x = -2 into the second equation:
y = 10 + 4(-2)
y = 10 - 8 = 2
I apologize for the error. The correct solution is x = -2 and y = 2.

Answer 6

Solve the system of equations.5x+2y=14 x−6y=22 (1 point)

Answer 7

The solution to the system of equations 5x+2y=14 and x−6y=22 is x = 4 and y = -3.

Answer 8

Solve the system of equations.–9x+y=12 2x+4y= −28 (1 point)

Answer 9

To solve the system of equations -9x+y=12 and 2x+4y=-28, we can use the method of substitution.

We'll start by solving the first equation for y in terms of x:

-9x + y = 12
y = 9x + 12

Now, plug this expression for y into the second equation:

2x + 4(9x + 12) = -28
2x + 36x + 48 = -28
38x + 48 = -28
38x = -76
x = -76/38
x = -2

Finally, substitute this value of x back into the first equation to find y:

-9(-2) + y = 12
18 + y = 12
y = 12 - 18
y = -6

Therefore, the solution to the system of equations is x = -2 and y = -6.

Answer 10

no

Answer 11

I apologize for the mistake. Let's solve the system of equations correctly:

We have the equations:
-9x + y = 12
2x + 4y = -28

To solve the system, we can choose to solve by substitution or elimination. In this case, let's solve it by elimination.

Multiply the first equation by 4 to make the coefficients of y in both equations the same:

-36x + 4y = 48

Now we have the system:
-36x + 4y = 48
2x + 4y = -28

Subtract the second equation from the first equation to eliminate y:

(-36x + 4y) - (2x + 4y) = 48 - (-28)
-36x + 4y - 2x - 4y = 48 + 28
-38x = 76

Solve for x:
-38x = 76
x = 76/(-38)
x = -2

Now substitute the value of x = -2 into one of the original equations. Let's use the first equation:

-9x + y = 12
-9(-2) + y = 12
18 + y = 12
y = 12 - 18
y = -6

Therefore, the solution to the system of equations is x = -2 and y = -6.

Answer 12

Solve the system of two equations using substitution.y=2+3x 4x−3y=−16 (1 point)

Answer 13

To solve the system of equations y=2+3x and 4x−3y=−16, we'll use the method of substitution.

First, we'll substitute the expression for y in terms of x from the first equation into the second equation:

4x - 3(2+3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -16 + 6
-5x = -10
x = -10 / -5
x = 2

Now, substitute this value of x back into the first equation to find y:

y = 2 + 3(2)
y = 2 + 6
y = 8

Therefore, the solution to the system of equations is x = 2 and y = 8.

Answer 14

Solve the system of equations.2x+6y=−18 x=5y−1 (1 point)

Answer 15

To solve the system of equations 2x+6y=−18 and x=5y−1, we'll use the method of substitution.

We'll start by substituting the expression for x from the second equation into the first equation:

2(5y - 1) + 6y = -18
10y - 2 + 6y = -18
16y - 2 = -18
16y = -16
y = -16 / 16
y = -1

Now, substitute this value of y back into the second equation to find x:

x = 5(-1) - 1
x = -5 - 1
x = -6

Therefore, the solution to the system of equations is x = -6 and y = -1.

Answer 16

Solve the system of equations.3x+y=2 7x−4y=30 (1 point)

Answer 17

To solve the system of equations 3x+y=2 and 7x−4y=30, we can use the method of substitution or elimination. Let's solve it using the elimination method.

We'll multiply the first equation by 4 and the second equation by 1 to eliminate y:

4(3x + y) = 4(2)
7x − 4y = 30

12x + 4y = 8
7x − 4y = 30

Now, add the two equations together:

12x + 4y + 7x − 4y = 8 + 30
19x = 38
x = 38/19
x = 2

Substitute the value of x back into the first equation to find y:

3(2) + y = 2
6 + y = 2
y = 2 - 6
y = -4

Therefore, the solution to the system of equations is x = 2 and y = -4.

Answer 18

Solve the system of equations.−4x+6y=38 x−5y=−20 (1 point)

Answer 19

To solve the system of equations −4x+6y=38 and x−5y=−20, we'll use the method of substitution.

We'll start by solving the second equation for x in terms of y:

x - 5y = -20
x = 5y - 20

Now, substitute the expression for x from the second equation into the first equation:

-4(5y - 20) + 6y = 38
-20y + 80 + 6y = 38
-14y = 38 - 80
-14y = -42
y = -42 / -14
y = 3

Now substitute the value of y back into the second equation to find x:

x - 5(3) = -20
x - 15 = -20
x = -20 + 15
x = -5

Therefore, the solution to the system of equations is x = -5 and y = 3.

Answer 20

How many solution(s) does the system of equations have?−5x+y=−18 10x−2y=36 (1 point)

Answer 21

To determine the number of solutions the system of equations −5x+y=−18 and 10x−2y=36 has, we can look at the slopes of the two lines formed by these equations.

The first equation, −5x+y=−18, can be rewritten as y = 5x - 18. This equation has a slope of 5.

The second equation, 10x−2y=36, can be rewritten as 2y = 10x - 36, or y = 5x - 18. This equation also has a slope of 5.

Since the slopes of the two equations are equal, the lines represented by the equations are parallel.

Parallel lines do not intersect, which means that the system of equations has no solution.

Therefore, the system of equations −5x+y=−18 and 10x−2y=36 has no solution.

Answer 22

thank u so much bot

Answer 23

You're welcome! I'm glad I could help. If you have any more questions, feel free to ask.