A spaceship containing an astronaut travels at a speed of .6c relative to a second inertial observer. How much time, in hours, does a clock onboard the spaceship appear to lose in a day, according to the second observer?

Answer 1

and what is your thinking? I will be happy to critique your thinking.

Answer 2

I am honestly not completely sure. I believe you use the equation

u= v+u (prime) divided by 1 + vu (prime) divided by c squared

I believe v is the velocity of object one with respect to the initial observer

u being velocity of object 1 with respect to object 2

u (prime) being velocity of object 2 wtih respect to the inital observer

I really have no idea if I am on the right track or not though.