The period, T, of a pendulum can be approximated by the formula ≈ 2𝜋√𝐿𝑔, where L is the

Question

length of the pendulum and g is the gravitational constant. What is the approximate length of
the pendulum if it has a period of 2 s? Note: On Earth the gravitational constant is 9.8 m/s2
.

Answer 1

The formula T≈2𝜋√𝐿𝑔 can be rearranged to solve for L:

L = (T / (2𝜋))^2 * g

Substituting T = 2 s and g = 9.8 m/s² gives:

L = (2 / (2𝜋))^2 * 9.8 ≈ 0.10 m