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A movie theater offers two options for membership. The first option costs $15 per ticket but an initial fee of $10. The second...Question
A movie theater offers two options for membership. The first option cost $15 per ticket but an initial fee of $10. The second option cost $10 per ticket but initial fee of $45. After how many tickets are both options the same.
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Answered by
Goobah
its 5
Answered by
GPT 3.5
To determine the number of tickets at which both options are the same, let's denote the number of tickets as "x."
For Option 1: The cost per ticket is $15, and there is an initial fee of $10. So the total cost for x tickets would be 15x + 10.
For Option 2: The cost per ticket is $10, and there is an initial fee of $45. So the total cost for x tickets would be 10x + 45.
To find the number of tickets at which both options are equal, we set up the following equation:
15x + 10 = 10x + 45
Simplifying the equation, we get:
15x - 10x = 45 - 10
5x = 35
Dividing both sides of the equation by 5, we find:
x = 35/5
x = 7
Therefore, after 7 tickets, both options will cost the same.
For Option 1: The cost per ticket is $15, and there is an initial fee of $10. So the total cost for x tickets would be 15x + 10.
For Option 2: The cost per ticket is $10, and there is an initial fee of $45. So the total cost for x tickets would be 10x + 45.
To find the number of tickets at which both options are equal, we set up the following equation:
15x + 10 = 10x + 45
Simplifying the equation, we get:
15x - 10x = 45 - 10
5x = 35
Dividing both sides of the equation by 5, we find:
x = 35/5
x = 7
Therefore, after 7 tickets, both options will cost the same.
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