A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership?(1 point)

Question

please respond bottt

Answer 1

To determine which membership would be cheaper for a year, let's calculate the cost for a year at each gym using the equation y = kx.

For Gym A:
Using the given information that the membership costs $50 for 5 months, we can write the equation as y = kx.
Considering x as the number of months and y as the cost, we have:
50 = 5k.

For Gym B:
Using the given information that the membership costs $40 for 3 months, we can write the equation as y = kx.
Considering x as the number of months and y as the cost, we have:
40 = 3k.

Now, we need to find the value of k for the cheaper membership. To do this, we will compare the cost for 12 months (a year) for each gym.

For Gym A:
If we multiply both sides of the equation 50 = 5k by 12 (months), we get:
600 = 60k.

For Gym B:
If we multiply both sides of the equation 40 = 3k by 12 (months), we get:
480 = 36k.

Comparing the coefficients of k in both equations, we see that the coefficient for Gym B (36k) is smaller than the coefficient for Gym A (60k).

Therefore, the value of k for the cheaper membership is 36.

Answer 2

wrong

Answer 3

Apologies for the incorrect response. Let's recalculate the value of k for the cheaper membership.

For Gym A:
The cost for Gym A for a year can be calculated by multiplying the cost for 5 months by 12 (months/year):
y = kx
y = 50*12
y = 600

So for Gym A, the equation becomes:
600 = kx

For Gym B:
The cost for Gym B for a year can be calculated by multiplying the cost for 3 months by 4 (quarters in a year):
y = kx
y = 40*4
y = 160

So for Gym B, the equation becomes:
160 = kx

Comparing the coefficients of k in both equations, we see that the coefficient for Gym B (160) is smaller than the coefficient for Gym A (600).

Therefore, the value of k for the cheaper membership is 160.

Answer 4

wrong, give me the right answer nowwww

Answer 5

Apologies for the confusion earlier. Let's recalculate the value of k for the cheaper membership correctly this time.

For Gym A:
The cost for Gym A for a year can be calculated by multiplying the cost for 5 months by 12 (months/year):
y = kx
y = 50*12
y = 600

So for Gym A, the equation becomes:
600 = kx

For Gym B:
The cost for Gym B for a year can be calculated by multiplying the cost for 3 months by 4 (quarters in a year):
y = kx
y = 40*4
y = 160

So for Gym B, the equation becomes:
160 = kx

Comparing the coefficients of k in both equations, we see that the coefficient for Gym B (160) is smaller than the coefficient for Gym A (600).

Therefore, the value of k for the cheaper membership is 160.

Answer 6

the answer is 10

Answer 7

Lmao