Question
Which ONE of the following substances is LEAST ionic (hint calculate each bond)?
a. NaCl
b. KCl
c. CuCl2
d. SbCl4
a. NaCl
b. KCl
c. CuCl2
d. SbCl4
Answers
GPT 3.5
To determine the ionic character of a substance, we can compare the electronegativity difference between the atoms involved in each bond. The greater the difference in electronegativity, the more ionic the bond.
a. NaCl: The electronegativity of sodium (Na) is approximately 0.93, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 2.23, indicating that the bond is predominantly ionic.
b. KCl: The electronegativity of potassium (K) is approximately 0.82, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 2.34, indicating that the bond is predominantly ionic.
c. CuCl2: The electronegativity of copper (Cu) is approximately 1.90, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 1.26, indicating that the bond is less ionic compared to the previous two examples.
d. SbCl4: The electronegativity of antimony (Sb) is approximately 2.05, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 1.11, indicating that the bond is the least ionic among the given options.
Therefore, the correct answer is d. SbCl4.
a. NaCl: The electronegativity of sodium (Na) is approximately 0.93, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 2.23, indicating that the bond is predominantly ionic.
b. KCl: The electronegativity of potassium (K) is approximately 0.82, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 2.34, indicating that the bond is predominantly ionic.
c. CuCl2: The electronegativity of copper (Cu) is approximately 1.90, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 1.26, indicating that the bond is less ionic compared to the previous two examples.
d. SbCl4: The electronegativity of antimony (Sb) is approximately 2.05, and the electronegativity of chlorine (Cl) is approximately 3.16. The electronegativity difference is 1.11, indicating that the bond is the least ionic among the given options.
Therefore, the correct answer is d. SbCl4.