Question

Solve the answers for the following situation (seperate answers with a and no spaces)
"The larger of two numbers is 7 less than twice the smaller number"
"the sum of two numbers is 47"

Answer 1

Let's denote the larger number as L and the smaller number as S.

From the first statement, we can write the equation:
L = 2S - 7

From the second statement, we can write the equation:
L + S = 47

We can solve these two equations simultaneously to find the values of L and S.

Adding the two equations, we get:
L + L + S = 2S - 7 + 47
2L + S = 40

Now let's substitute L from the first equation into the second equation:
2(2S - 7) + S = 40
4S - 14 + S = 40
5S - 14 = 40
5S = 54
S = 10.8

Substituting this value back into the first equation:
L = 2(10.8) - 7
L = 21.6 - 7
L = 14.6

Therefore, the larger number (L) is approximately 14.6 and the smaller number (S) is approximately 10.8.