To find the number of bacteria after 5 hours, we can plug in t=5 into the function B(t).
B(5) = 300(2)^5
B(5) = 300(32)
B(5) = 9600
Therefore, there will be 9600 bacteria after 5 hours.
The function B(t) = 300(2)t
gives the number of bacteria after t
hours. How many bacteria exist after 5 hours? (1 point)
Responses
7.776 ×1013
7.776 ×1013
t= 5
t= 5
3000
3000
9600
9600
1 answer