Question

Please complete each question in “given & required/formula(s)/solutions/answer” (GRASS) format. Clearly label all cases (a, b). Answers must be clear to read and show all steps.

An object is pushed along a rough horizontal surface and released. It slides for 11.0 s before coming to rest and travels a distance of 22.0 cm during the last 1.5 s of its slide. Assuming the acceleration to be uniform throughout
(a) How fast was the object travelling upon release?
(b) How fast was the object travelling when it reached the halfway position in its slide?
Answer
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Answer
are these answer correct?
Answer
I got 2.156 m/s for a)
Answer
bot, are you sure?
Answer
a) Time taken to slide t = 11s
Distance traveled during 1.5s, s=22cm = 0.22m

D = V2t – (1/2) at^2
2d/-t^2= a

-2(0.22) / (1.5)^2 = a
-0.196 m/s^2 = a

a = (V2 – V1) / t
V2 – V1 =at
V2 – at = V1

0 – (-0.196m/s) (11) = v1
2.156 m/s = V1

is this correct?
Answer
b) Time taken to slide t = 11s
V1 = 2.156 m/s
T = 11s
V2 = 0
D =?

D = v1 t + ½ at2
D = (2.156m/s) (11s) + ½ (-0.196m/s2) (10s)2
D = 13.92m

Halfway position = 11m
V1 = 2.156 m/s
A = -0.196 m/s2

2 ad = V22 – V12

V12 + 2ad = V22

(2.156 m/s) 2 + 2 (-0.196 m/s2) (11m) = V22
0.336m/s = V22
√0.336m/s = V2
0.58m/s = V2

is this correct?
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