Is (-2,6)a solution to the system of these liner equations x+ 2y=10 and 3x+y=0? why

Answer 1

To determine if (-2, 6) is a solution to the system of linear equations, we substitute the values of x and y into each equation and check if the equations hold true.

For the first equation:
x + 2y = 10
Substituting x = -2 and y = 6:
(-2) + 2(6) = 10
-2 + 12 = 10
10 = 10

This equation is true, so (-2, 6) satisfies the first equation.

For the second equation:
3x + y = 0
Substituting x = -2 and y = 6:
3(-2) + 6 = 0
-6 + 6 = 0
0 = 0

This equation is also true, so (-2, 6) satisfies the second equation.

Since (-2, 6) satisfies both equations, it is a solution to the system of linear equations.