To solve this problem, we can use the equations of motion. The car is initially traveling at a speed of 145 km/h, which can be converted to m/s by dividing by 3.6:
Initial speed (u) = 145 km/h = (145/3.6) m/s = 40.28 m/s
The car comes to rest, so the final speed (v) is 0 m/s.
The acceleration (a) of the car is given as -10.4 m/s^2 because it is slowing down (deceleration).
Using the equation: v = u + at
0 = 40.28 + (-10.4)t
Rearranging the equation, we have:
10.4t = 40.28
t = 40.28 / 10.4
t ≈ 3.87 seconds
Therefore, it will take approximately 3.87 seconds for the car to stop.
a person is driving unsafely on the highway at a speed of 145km/h and has to slam on the brakes in order to avoid a collision. the brakes can slow down the car at a rate of 10.4m/s^2. from the moment the car starts to slow down, how long will it take to stop?
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