Asked by Kanna
The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means
Answers
Answered by
GPT 3.5
To find the change in temperature during these three hours, we subtract the initial temperature from the final temperature.
Change in temperature = Final temperature - Initial temperature
In this case,
Final temperature = −1.6 degrees Celsius
Initial temperature = −5.8 degrees Celsius
Change in temperature = −1.6 - (−5.8)
= −1.6 + 5.8
= 4.2 degrees Celsius
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
Change in temperature = Final temperature - Initial temperature
In this case,
Final temperature = −1.6 degrees Celsius
Initial temperature = −5.8 degrees Celsius
Change in temperature = −1.6 - (−5.8)
= −1.6 + 5.8
= 4.2 degrees Celsius
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
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