Asked by Angie
                What are you supposed to get when you factor 3q^2+16q=-5? I got (q+3)(3q+1)
            
            
        Answers
                    Answered by
            chris
            
    3q^2+16q= -5
3q^2+16q+5 = 0 now look for factors of 15 that add to be 16 (1 &15)
so (3q + 1)(q +1) = 0
so (3q + 1) = 0 and/or (q +1) = 0
so{-1/3, -1} are your possible solutions
    
3q^2+16q+5 = 0 now look for factors of 15 that add to be 16 (1 &15)
so (3q + 1)(q +1) = 0
so (3q + 1) = 0 and/or (q +1) = 0
so{-1/3, -1} are your possible solutions
                    Answered by
            Angie
            
    How did you get (3q + 1)(q +1) = 0? What happened to the 15? 
    
                    Answered by
            PsyDAG
            
    There is a typo in the previous information.
3q^2 + 16q + 5 = (3q + 1)(q + 5) = 0
3 * 5 = 15
so q could = -1/3 or -5
This should make it clearer. Thanks for asking.
    
3q^2 + 16q + 5 = (3q + 1)(q + 5) = 0
3 * 5 = 15
so q could = -1/3 or -5
This should make it clearer. Thanks for asking.
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