The 8 LEDs on the Explorer 16 development board to generate a Knight Rider Pattern on those LEDs.Calculations (Current/voltage/resistance/Time/Frequency/ etc.,):

Answer 1

To generate a Knight Rider pattern on the 8 LEDs of the Explorer 16 development board, we need to consider the current, voltage, resistance, time, and frequency of the pattern.

1. Current: Each LED on the board will require a specific current to illuminate properly. Check the datasheet or technical specifications of the LEDs to determine their forward current (typically given in milliamperes or mA).

2. Voltage: The LEDs will also have a forward voltage requirement. It is important to ensure that the source voltage meets or exceeds this forward voltage. The Explorer 16 development board usually operates at 3.3V or 5V, so check the specifications accordingly.

3. Resistance: A resistor is typically required in series with each LED to limit the current flowing through it. The value of the resistor can be calculated using Ohm's Law (R = V/I), where R is the resistance, V is the voltage across the resistor, and I is the desired current for the LED.

4. Time: The time it takes for each LED to turn on and off in the Knight Rider pattern can be determined based on the desired pattern speed. For example, if you want each LED to stay illuminated for 1 second before moving to the next one, the time would be 1 second for each LED.

5. Frequency: The frequency refers to how quickly the LEDs transition from one to another in the pattern. The frequency can be calculated as the reciprocal of the time period for each LED.

Overall, the calculations will depend on the specific LEDs used, the desired current and voltage, and the timing requirements of the pattern. It is recommended to consult the datasheets of the components used and refer to the circuit diagram of the Explorer 16 development board for more accurate calculations.

Answer 2

Voltage: +3.3V
Resistance: 10k

Answer 3

If the voltage is +3.3V and a resistance of 10k is used, we can calculate the current flowing through the circuit using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance.

I = 3.3V / 10kΩ
I = 0.33mA

Therefore, with a voltage of +3.3V and a resistance of 10kΩ, the current flowing through the circuit would be approximately 0.33mA. Make sure to check the forward current specifications of the LEDs to ensure it is within their operating limits.