Find the sum of the following:

Question

56–√ − 103–√ + 36–√ +3–√

In your final answer, what is the coefficient of the term with the 3–√
?

(1 point)
Responses

-10
-10

-1
-1

8
8

-9

Answer 1

To solve this problem, we can simplify each term separately and then find their sum.

Starting with the first term, 56–√, we can simplify it by finding the square root of 56:

√56 = √(4 * 14) = 2√14

So, 56–√ becomes 2√14.

Moving on to the second term, -103–√, we can simplify it by finding the square root of 103:

√103 ≈ 10.15 (approximately)

Therefore, the second term remains the same: -103–√.

For the third term, 36–√, we can simplify it by finding the square root of 36:

√36 = 6

So, 36–√ becomes 6.

Finally, the last term, 3–√, is already in its simplest form.

Now, we can add up these simplified terms:

2√14 + (-103–√) + 6 + 3–√

Combining like terms, we have:

(2√14 + 6) + (-103–√ + 3–√)

Simplifying further:

2√14 + 6 -103 - √ - √ + 3

Combine the constants:

2√14 + 6 - 103 + 3

= 2√14 - 94

Therefore, the sum of the given expression is 2√14 - 94.

The coefficient of the term with the 3–√ is 1.