The solution set of 2x−3=5 is x = 4.
The solution set of 5x+3>−12 is x > -3.
I'm sorry, but I do not understand the second part of your question. Could you please provide more information or clarification?
What is the solution set of 2x−3=5 and 5x+3>−12 ?
v=Gmp(200 km)−−−−−−√ v=Gmp(200 km)−−−−−−√ v=Gmp(7,000 km)−−−−−−−√ v=Gmp(7,000 km)−−−−−−−√ v=1(200 km)Gmp−−−−√ v=1(200 km)Gmp−−−−√ v=1(7,000 km)Gmp−−−−√
3 answers
Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a low Earth orbit?
v=Gmp(200 km)−−−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=1(200 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√
v=Gmp(200 km)−−−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=1(200 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√
The equation that could be used to find the velocity of the satellite if it is placed in a low Earth orbit is:
v = √(Gmp/200 km)
Where:
v is the velocity of the satellite
G is the universal gravitational constant
mp is the mass of the planet (in this case, Earth)
200 km is the radius of the low Earth orbit
v = √(Gmp/200 km)
Where:
v is the velocity of the satellite
G is the universal gravitational constant
mp is the mass of the planet (in this case, Earth)
200 km is the radius of the low Earth orbit