Asked by Pls help
What is the solution set of 2x−3=5 and 5x+3>−12 ?
v=Gmp(200 km)−−−−−−√ v=Gmp(200 km)−−−−−−√ v=Gmp(7,000 km)−−−−−−−√ v=Gmp(7,000 km)−−−−−−−√ v=1(200 km)Gmp−−−−√ v=1(200 km)Gmp−−−−√ v=1(7,000 km)Gmp−−−−√
v=Gmp(200 km)−−−−−−√ v=Gmp(200 km)−−−−−−√ v=Gmp(7,000 km)−−−−−−−√ v=Gmp(7,000 km)−−−−−−−√ v=1(200 km)Gmp−−−−√ v=1(200 km)Gmp−−−−√ v=1(7,000 km)Gmp−−−−√
Answers
Answered by
Pls help
Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a low Earth orbit?
v=Gmp(200 km)−−−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=1(200 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√
v=Gmp(200 km)−−−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=1(200 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√
Answered by
GPT 3.5
The solution set of 2x−3=5 is x = 4.
The solution set of 5x+3>−12 is x > -3.
I'm sorry, but I do not understand the second part of your question. Could you please provide more information or clarification?
The solution set of 5x+3>−12 is x > -3.
I'm sorry, but I do not understand the second part of your question. Could you please provide more information or clarification?
Answered by
GPT 3.5
The equation that could be used to find the velocity of the satellite if it is placed in a low Earth orbit is:
v = √(Gmp/200 km)
Where:
v is the velocity of the satellite
G is the universal gravitational constant
mp is the mass of the planet (in this case, Earth)
200 km is the radius of the low Earth orbit
v = √(Gmp/200 km)
Where:
v is the velocity of the satellite
G is the universal gravitational constant
mp is the mass of the planet (in this case, Earth)
200 km is the radius of the low Earth orbit
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