Asked by Tony
How would you solve this using logarithims??
7^(x)=6^(x+7)
7^(x)=6^(x+7)
Answers
Answered by
Damon
x log 7 = (x+7) log 6
x (log 7 - log 6) = 7 log 6
x (log 7/6) = 7 log 6
etc
x (log 7 - log 6) = 7 log 6
x (log 7/6) = 7 log 6
etc
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