Question

A game has the following rules. A fair die is tossed. The tosser wins $7 if a
1 or 2 shows and wins $11 if a 6 shows. The tosser pays $14 if a 3 shows and $6 if a 4 or 5
shows. The tosser's expected winnings for one toss is closest to?

Answer 1

Each side has a 1/6 chance of occurring. Multiply each value by the chance for each side. The either-or probability of the 6 choices is found by adding these products.

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