The irrational cube root ∛(-24) can be rewritten as a product of an integer and another irrational cube root by factoring out any perfect cube from -24.
The factors of -24 are:
± 1, ± 2, ± 3, ± 4, ± 6, ± 8, ± 12, and ± 24.
None of these numbers are perfect cubes, so we cannot rewrite ∛(-24) as a product of an integer and another irrational cube root.
what is the irrational cube root 3√-24 rewritten as a product of an integer and another irrational cube root
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do it right
Apologies for the confusion. Let's rewrite ∛(-24) as a product of an integer and another irrational cube root.
To do this, we need to find a perfect cube factor of -24. The perfect cube factors of -24 are ±8.
So, we can rewrite ∛(-24) as 2∛(-8).
Therefore, the irrational cube root ∛(-24) can be rewritten as a product of an integer (2) and another irrational cube root (∛(-8)).
To do this, we need to find a perfect cube factor of -24. The perfect cube factors of -24 are ±8.
So, we can rewrite ∛(-24) as 2∛(-8).
Therefore, the irrational cube root ∛(-24) can be rewritten as a product of an integer (2) and another irrational cube root (∛(-8)).
1 answer