Asked by Yaneth

a population of 600 plants contains 294 AA, 252 Aa, and 54 aa individuals. the AA and Aa produce purple flowers while the aa plants produce white flowers. what are the frequencies of the following? please show work or explain how you got it. please

A. Allele A
B. Allele a
C. Genotype AA
D. Genotype Aa
E. Genotype aa
F. purple flowered plants
G. white flowered plants
Answered by PsyDAG
Your total is 600 individuals. Divide the individuals in each category by 600.

A. If both the AA and Aa individuals have Allele A, then the proportion of individuals with Allele A = (294 + 252)/600. However, if you want the proportion of times that A occurs in the gene pairs, this is ([2*294] + 252)/(2*600).

Proceed in a similar way with the other problems.

I hope this helps. Thanks for asking.


Answered by RickP
a population of 600 plants contains 294 AA, 252 Aa, and 54 aa individuals. the AA and Aa produce purple flowers while the aa plants produce white flowers. what are the frequencies of the following? please show work or explain how you got it. please

A. Allele A
B. Allele a
C. Genotype AA
D. Genotype Aa
E. Genotype aa
F. purple flowered plants
G. white flowered plants

There are 600 plants, each with 2 alleles. That gives a total of 1200 alleles in the population.

Since each of 294 AA individuals has 2 alleles, and each of 252 Aa individuals has 1 A allele:
A alleles = (294 * 2) + (252 * 1) = 588 + 252 = 840

Same general logic goes for a alleles:
a alleles = (252 * 1) + (54 * 2) = 252 + 108 = 360

F(A) = A alleles / total alleles
F(A) = 840/1200
F(A) = 7/10

F(a) = a alleles / total alleles
F(a) = 360/1200
F(a) = 3/10


Answered by RickP
The genotype frequencies are much easier to calculate.

F(AA) = # of AA individuals / 600

F(Aa) = # of Aa individuals / 600

F(aa) = # of aa individuals / 600
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