Let's represent the air temperature at 9 am with the variable T1 and the air temperature at noon with the variable T2.
Based on the given information, we know that T1 = -5.8 degrees Celsius and T2 = -1.6 degrees Celsius.
To find the equation, we can use the fact that the temperature increases by the same amount every hour. The time difference between 9 am and noon is 3 hours. Therefore, the temperature increased by the same amount over 3 hours.
We need to find the change in temperature per hour. We can do this by subtracting T1 from T2 and dividing it by the number of hours:
Change in temperature per hour = (T2 - T1) / 3
Plugging in the values, we have:
Change in temperature per hour = (-1.6 - (-5.8)) / 3
Change in temperature per hour = (-1.6 + 5.8) / 3
Change in temperature per hour = 4.2 / 3
Change in temperature per hour ≈ 1.4 degrees Celsius
The equation to show the answer is T2 = T1 + (1.4 * 3)
Now let's solve the equation:
T2 = -5.8 + (1.4 * 3)
T2 = -5.8 + 4.2
T2 = -1.6
Therefore, our answer is T2 = -1.6 degrees Celsius.
This means that the air temperature increased by 1.4 degrees Celsius every hour between 9 am and noon. The temperature at 9 am was -5.8 degrees Celsius, and 3 hours later at noon, the temperature became -1.6 degrees Celsius.
the air temperature at 9 am is -5.8 degrees Celsius. the air temperature at noon is -1.6 degrees Celsius. write and solve and equation to show your answer. then explain what your answer means.
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